Optimal. Leaf size=326 \[ -\frac {224 \sqrt {2-\sqrt {3}} b^2 \sqrt [6]{a+b x^2} \left (1-\sqrt [3]{\frac {a}{a+b x^2}}\right ) \sqrt {\frac {\left (\frac {a}{a+b x^2}\right )^{2/3}+\sqrt [3]{\frac {a}{a+b x^2}}+1}{\left (-\sqrt [3]{\frac {a}{a+b x^2}}-\sqrt {3}+1\right )^2}} \operatorname {EllipticF}\left (\sin ^{-1}\left (\frac {-\sqrt [3]{\frac {a}{a+b x^2}}+\sqrt {3}+1}{-\sqrt [3]{\frac {a}{a+b x^2}}-\sqrt {3}+1}\right ),4 \sqrt {3}-7\right )}{135 \sqrt [4]{3} a^3 x \sqrt [3]{\frac {a}{a+b x^2}} \sqrt {-\frac {1-\sqrt [3]{\frac {a}{a+b x^2}}}{\left (-\sqrt [3]{\frac {a}{a+b x^2}}-\sqrt {3}+1\right )^2}}}-\frac {112 b^2 \sqrt [6]{a+b x^2}}{135 a^3 x}+\frac {14 b \sqrt [6]{a+b x^2}}{45 a^2 x^3}-\frac {\sqrt [6]{a+b x^2}}{5 a x^5} \]
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Rubi [A] time = 0.28, antiderivative size = 326, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {325, 241, 236, 219} \[ -\frac {112 b^2 \sqrt [6]{a+b x^2}}{135 a^3 x}-\frac {224 \sqrt {2-\sqrt {3}} b^2 \sqrt [6]{a+b x^2} \left (1-\sqrt [3]{\frac {a}{a+b x^2}}\right ) \sqrt {\frac {\left (\frac {a}{a+b x^2}\right )^{2/3}+\sqrt [3]{\frac {a}{a+b x^2}}+1}{\left (-\sqrt [3]{\frac {a}{a+b x^2}}-\sqrt {3}+1\right )^2}} F\left (\sin ^{-1}\left (\frac {-\sqrt [3]{\frac {a}{b x^2+a}}+\sqrt {3}+1}{-\sqrt [3]{\frac {a}{b x^2+a}}-\sqrt {3}+1}\right )|-7+4 \sqrt {3}\right )}{135 \sqrt [4]{3} a^3 x \sqrt [3]{\frac {a}{a+b x^2}} \sqrt {-\frac {1-\sqrt [3]{\frac {a}{a+b x^2}}}{\left (-\sqrt [3]{\frac {a}{a+b x^2}}-\sqrt {3}+1\right )^2}}}+\frac {14 b \sqrt [6]{a+b x^2}}{45 a^2 x^3}-\frac {\sqrt [6]{a+b x^2}}{5 a x^5} \]
Antiderivative was successfully verified.
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Rule 219
Rule 236
Rule 241
Rule 325
Rubi steps
\begin {align*} \int \frac {1}{x^6 \left (a+b x^2\right )^{5/6}} \, dx &=-\frac {\sqrt [6]{a+b x^2}}{5 a x^5}-\frac {(14 b) \int \frac {1}{x^4 \left (a+b x^2\right )^{5/6}} \, dx}{15 a}\\ &=-\frac {\sqrt [6]{a+b x^2}}{5 a x^5}+\frac {14 b \sqrt [6]{a+b x^2}}{45 a^2 x^3}+\frac {\left (112 b^2\right ) \int \frac {1}{x^2 \left (a+b x^2\right )^{5/6}} \, dx}{135 a^2}\\ &=-\frac {\sqrt [6]{a+b x^2}}{5 a x^5}+\frac {14 b \sqrt [6]{a+b x^2}}{45 a^2 x^3}-\frac {112 b^2 \sqrt [6]{a+b x^2}}{135 a^3 x}-\frac {\left (224 b^3\right ) \int \frac {1}{\left (a+b x^2\right )^{5/6}} \, dx}{405 a^3}\\ &=-\frac {\sqrt [6]{a+b x^2}}{5 a x^5}+\frac {14 b \sqrt [6]{a+b x^2}}{45 a^2 x^3}-\frac {112 b^2 \sqrt [6]{a+b x^2}}{135 a^3 x}-\frac {\left (224 b^3\right ) \operatorname {Subst}\left (\int \frac {1}{\left (1-b x^2\right )^{2/3}} \, dx,x,\frac {x}{\sqrt {a+b x^2}}\right )}{405 a^3 \sqrt [3]{\frac {a}{a+b x^2}} \sqrt [3]{a+b x^2}}\\ &=-\frac {\sqrt [6]{a+b x^2}}{5 a x^5}+\frac {14 b \sqrt [6]{a+b x^2}}{45 a^2 x^3}-\frac {112 b^2 \sqrt [6]{a+b x^2}}{135 a^3 x}+\frac {\left (112 b^2 \sqrt {-\frac {b x^2}{a+b x^2}} \sqrt [6]{a+b x^2}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{\frac {a}{a+b x^2}}\right )}{135 a^3 x \sqrt [3]{\frac {a}{a+b x^2}}}\\ &=-\frac {\sqrt [6]{a+b x^2}}{5 a x^5}+\frac {14 b \sqrt [6]{a+b x^2}}{45 a^2 x^3}-\frac {112 b^2 \sqrt [6]{a+b x^2}}{135 a^3 x}-\frac {224 \sqrt {2-\sqrt {3}} b^2 \sqrt {-\frac {b x^2}{a+b x^2}} \sqrt [6]{a+b x^2} \left (1-\sqrt [3]{\frac {a}{a+b x^2}}\right ) \sqrt {\frac {1+\sqrt [3]{\frac {a}{a+b x^2}}+\left (\frac {a}{a+b x^2}\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{\frac {a}{a+b x^2}}\right )^2}} F\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-\sqrt [3]{\frac {a}{a+b x^2}}}{1-\sqrt {3}-\sqrt [3]{\frac {a}{a+b x^2}}}\right )|-7+4 \sqrt {3}\right )}{135 \sqrt [4]{3} a^3 x \sqrt [3]{\frac {a}{a+b x^2}} \sqrt {-\frac {1-\sqrt [3]{\frac {a}{a+b x^2}}}{\left (1-\sqrt {3}-\sqrt [3]{\frac {a}{a+b x^2}}\right )^2}} \sqrt {-1+\frac {a}{a+b x^2}}}\\ \end {align*}
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Mathematica [C] time = 0.01, size = 51, normalized size = 0.16 \[ -\frac {\left (\frac {b x^2}{a}+1\right )^{5/6} \, _2F_1\left (-\frac {5}{2},\frac {5}{6};-\frac {3}{2};-\frac {b x^2}{a}\right )}{5 x^5 \left (a+b x^2\right )^{5/6}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.64, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (b x^{2} + a\right )}^{\frac {1}{6}}}{b x^{8} + a x^{6}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (b x^{2} + a\right )}^{\frac {5}{6}} x^{6}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.31, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (b \,x^{2}+a \right )^{\frac {5}{6}} x^{6}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (b x^{2} + a\right )}^{\frac {5}{6}} x^{6}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {1}{x^6\,{\left (b\,x^2+a\right )}^{5/6}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 1.49, size = 32, normalized size = 0.10 \[ - \frac {{{}_{2}F_{1}\left (\begin {matrix} - \frac {5}{2}, \frac {5}{6} \\ - \frac {3}{2} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{5 a^{\frac {5}{6}} x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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